Remove "called on standard input" message

This was printed basically everywhere.

The user knows what they executed on standard input.

A good example:

```fish
set c (subme 513)
```

used to print

```
fish: Too much data emitted by command substitution so it was discarded

    set -l x (string repeat -n $argv x)
             ^
in function 'subme'
	called on standard input
	with parameter list '513'
in command substitution
	called on standard input
```

and now it is

```
fish: Too much data emitted by command substitution so it was discarded

    set -l x (string repeat -n $argv x)
             ^
in function 'subme' with arguments '513'
in command substitution
```

See #5434.

src/parser.cpp

@@ -405,6 +405,7 @@ void parser_t::stack_trace_internal(size_t block_idx, wcstring *buff) const {
             }
         }
 
+        // Print where the function is called.
         const wchar_t *file = b->src_filename;
 
         if (file) {
@@ -413,9 +414,9 @@ void parser_t::stack_trace_internal(size_t block_idx, wcstring *buff) const {
         } else if (is_within_fish_initialization()) {
             append_format(*buff, _(L"\tcalled during startup\n"));
         } else {
-            append_format(*buff, _(L"\tcalled on standard input\n"));
+            // This one is way too noisy
+            // append_format(*buff, _(L"\tcalled on standard input\n"));
         }
-
     }
 
     // Recursively print the next block.

tests/test_cmdsub.err

@@ -15,11 +15,8 @@ fish: Too much data emitted by command substitution so it was discarded
 
     set -l x (string repeat -n $argv x)
              ^
-in function 'subme'
-	called on standard input
-	with parameter list '513'
+in function 'subme' with arguments '513'
 in command substitution
-	called on standard input
 
 ####################
 # Make sure output from builtins outside of command substitution is not affected