# # Find files that complete $argv[1], has the suffix $argv[2], and output them # as completions with the optional description $argv[3]. Then, also output # completions for the files that don't have the suffix, so you want to use # "complete -k" on the output. Both $argv[1] and $argv[3] are optional, # if only one is specified, it is assumed to be the argument to complete. If # $argv[4] is present, it is treated as a prefix for the path, i.e. in lieu # of $PWD. function __fish_complete_suffix -d "Complete using files" # Variable declarations set -l comp set -l suff set -l desc set -l files set -l prefix "" switch (count $argv) case 1 set comp (commandline -ct) set suff $argv set desc "" case 2 set comp $argv[1] set suff $argv[2] set desc "" case 3 set comp $argv[1] set suff $argv[2] set desc $argv[3] case 4 set comp $argv[1] set suff $argv[2] set desc $argv[3] set prefix $argv[4] # Only directories are supported as prefixes, and to use the same logic # for both absolute prefixed paths and relative non-prefixed paths, $prefix # must terminate in a `/` if it is present, so it can be unconditionally # prefixed to any path to get the desired result. if not string match -qr '/$' $prefix set prefix $prefix/ end end # Simple and common case: no prefix, just complete normally and sort matching files first. if test -z $prefix set -l suffix (string escape --style=regex -- $suff) # Use normal file completions. set files (complete -C "__fish_command_without_completions $comp") set -l files_with_suffix (string match -r -- "^.*$suffix\$" $files) set -l directories (string match -r -- '^.*/$' $files) set files $files_with_suffix $directories $files else # Strip leading ./ as it confuses the detection of base and suffix # It is conditionally re-added below. set base $prefix(string replace -r '^("\')?\\./' '' -- $comp | string trim -c '\'"') # " make emacs syntax highlighting happy set -l all set -l files_with_suffix set -l dirs # If $comp is "./ma" and the file is "main.py", we'll catch that case here, # but complete.cpp will not consider it a match, so we have to output the # correct form. # Also do directory completion, since there might be files with the correct # suffix in a subdirectory. set all $base* set files_with_suffix (string match -r -- ".*"(string escape --style=regex -- $suff) $all) if not string match -qr '/$' -- $suff set dirs $base*/ # The problem is that we now have each directory included twice in the output, # once as `dir` and once as `dir/`. The runtime here is O(n) for n directories # in the output, but hopefully since we have only one level (no nested results) # it should be fast. The alternative is to shell out to `sort` and remove any # duplicate results, but it would have to be a huge `n` to make up for the fork # overhead. for dir in $dirs set all (string match -v (string match -r '(.*)/$' -- $dir)[2] -- $all) end end set files $files_with_suffix $dirs $all if string match -qr '^\\./' -- $comp set files ./$files else # "Escape" files starting with a literal dash `-` with a `./` set files (string replace -r -- "^-" "./-" $files) end end if set -q files[1] if string match -qr -- . "$desc" set desc "\t$desc" end if string match -qr -- . "$prefix" set prefix (string escape --style=regex -- $prefix) set files (string replace -r -- "^$prefix" "" $files) end printf "%s$desc\n" $files end end