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4b079e16e5
Variables set in if and while conditions are in the enclosing block, not
the if/while statement block. For example:
if set -l var (somecommand) ; end
echo $var
will now work as expected.
Fixes #4820. Fixes #1212.
52 lines
1.5 KiB
Fish
52 lines
1.5 KiB
Fish
# Test index ranges
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logmsg Test variable expand
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set n 10
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set test (seq $n)
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echo $test[1..$n] # normal range
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echo $test[$n..1] # inverted range
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echo $test[2..5 8..6] # several ranges
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echo $test[-1..-2] # range with negative limits
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echo $test[-1..1] # range with mixed limits
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logmsg Test variable set
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set test1 $test
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set test1[-1..1] $test; echo $test1
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set test1[1..$n] $test; echo $test1
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set test1[$n..1] $test; echo $test1
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set test1[2..4 -2..-4] $test1[4..2 -4..-2]; echo $test1
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logmsg Test using slices of command substitution
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echo (seq 5)[-1..1]
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echo (seq $n)[3..5 -2..2]
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logmsg Test more
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echo $test[(count $test)..1]
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echo $test[1..(count $test)]
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# See issue 1061
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logmsg Verify that if statements swallow failure
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if false ; end ; echo $status
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logmsg Verify and/or behavior with if and while statements
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if false ; or true ; echo "success1" ; end
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if false ; and false ; echo "failure1" ; end
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while false ; and false ; or true ; echo "success2"; break ; end
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while false; or begin ; false; or true; end; echo "success3"; break ; end
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if false ; else if false ; and true ; else if false ; and false ; else if false; or true; echo "success4"; end
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if false ; else if false ; and true ; else if false ; or false ; else if false; echo "failure 4"; end
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if false ; or true | false ; echo "failure5" ; end
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logmsg Catch this corner case, which should produce an error
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if false ; or --help ; end
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logmsg Loop control in conditions
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for i in 1 2 3
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while break; end
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echo $i
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end
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for i in 1 2 3
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while continue; end
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echo $i
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end
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