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2c77b24ced
The BSD `seq` command handles `seq 0` weird.
19 lines
613 B
Fish
19 lines
613 B
Fish
# Show information about the named var(s) passed to us.
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function show --no-scope-shadowing
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for v in $argv
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if set -q $v
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set -l c (count $$v)
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printf '$%s count=%d\n' $v $c
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# This test is to work around a bogosity of the BSD `seq` command. If called with
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# `seq 0` it emits `1`, `0`. Whereas that GNU version outputs nothing.
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if test $c -gt 0
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for i in (seq $c)
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printf '$%s[%d]=|%s|\n' $v $i $$v[1][$i]
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end
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end
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else
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echo \$$v is not set
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end
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end
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end
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