fish-shell/share/functions/seq.fish
Fabian Homborg 53fc9a4002 Remove circular dependency in fallback seq
This was subtle because `type` invoked seq.

Fixes #2570
2015-11-27 19:34:27 +01:00

49 lines
1.0 KiB
Fish

# If seq is not installed, then define a function that invokes __fish_fallback_seq
# We can't call type here because that also calls seq
if not command -s seq >/dev/null
# No seq command
function seq --description "Print sequences of numbers"
__fish_fallback_seq $argv
end
function __fish_fallback_seq --description "Fallback implementation of the seq command"
set -l from 1
set -l step 1
set -l to 1
switch (count $argv)
case 1
set to $argv[1]
case 2
set from $argv[1]
set to $argv[2]
case 3
set from $argv[1]
set step $argv[2]
set to $argv[3]
case '*'
printf (_ "%s: Expected 1, 2 or 3 arguments, got %d\n") seq (count $argv)
return 1
end
for i in $from $step $to
if not echo $i | grep -E '^-?[0-9]*([0-9]*|\.[0-9]+)$' >/dev/null
printf (_ "%s: '%s' is not a number\n") seq $i
return 1
end
end
if [ $step -ge 0 ]
echo "for( i=$from; i<=$to ; i+=$step ) i;" | bc
else
echo "for( i=$from; i>=$to ; i+=$step ) i;" | bc
end
end
end