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53fc9a4002
This was subtle because `type` invoked seq. Fixes #2570
49 lines
1.0 KiB
Fish
49 lines
1.0 KiB
Fish
# If seq is not installed, then define a function that invokes __fish_fallback_seq
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# We can't call type here because that also calls seq
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if not command -s seq >/dev/null
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# No seq command
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function seq --description "Print sequences of numbers"
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__fish_fallback_seq $argv
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end
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function __fish_fallback_seq --description "Fallback implementation of the seq command"
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set -l from 1
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set -l step 1
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set -l to 1
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switch (count $argv)
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case 1
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set to $argv[1]
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case 2
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set from $argv[1]
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set to $argv[2]
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case 3
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set from $argv[1]
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set step $argv[2]
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set to $argv[3]
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case '*'
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printf (_ "%s: Expected 1, 2 or 3 arguments, got %d\n") seq (count $argv)
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return 1
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end
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for i in $from $step $to
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if not echo $i | grep -E '^-?[0-9]*([0-9]*|\.[0-9]+)$' >/dev/null
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printf (_ "%s: '%s' is not a number\n") seq $i
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return 1
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end
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end
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if [ $step -ge 0 ]
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echo "for( i=$from; i<=$to ; i+=$step ) i;" | bc
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else
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echo "for( i=$from; i>=$to ; i+=$step ) i;" | bc
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end
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end
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end
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