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Ensure backward compatible testing of types (#1266)
- Use "type(0)" instead of "v:t_number" - Use "==" instead of "==#" since we are comparing numbers - Make use of the "+=" operator - Update the "CHANGELOG.md" file The only real issue here is that we should prefer "type(0)" over the special variable. I run into this problem enough on older systems that it frustrates me. Let's have it fixed!
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@ -5,7 +5,8 @@
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- **.PATCH**: Pull Request Title (PR Author) [PR Number](Link to PR)
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-->
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#### 6.10
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- **.14**: Replace trim() with a version-compatible alternative. (PhilRunninger) [#1265](https://github.com/preservim/nerdtree/pull/1265)
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- **.15**: Ensure backward compatible testing of types. (lifecrisis) [#1266](https://github.com/preservim/nerdtree/pull/1266)
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- **.14**: Replace trim() with a version-compatible alternative. (PhilRunninger) [#1265](https://github.com/preservim/nerdtree/pull/1265)
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- **.13**: Change highlighting of bookmarks in the tree. (PhilRunninger) [#1261](https://github.com/preservim/nerdtree/pull/1261)
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- **.12**: Answer the question about accessing files over scp or ftp. (PhilRunninger) [#1259](https://github.com/preservim/nerdtree/pull/1259)
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- **.11**: Trim filenames created via the fs_menu (elanorigby) [#1243](https://github.com/preservim/nerdtree/pull/1243)
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@ -112,18 +112,18 @@ function! nerdtree#compareNodePaths(p1, p2) abort
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" Compare chunks upto common length.
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" If chunks have different type, the one which has
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" integer type is the lesser.
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if type(sortKey1[i]) ==# type(sortKey2[i])
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if type(sortKey1[i]) == type(sortKey2[i])
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if sortKey1[i] <# sortKey2[i]
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return - 1
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elseif sortKey1[i] ># sortKey2[i]
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return 1
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endif
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elseif type(sortKey1[i]) ==# v:t_number
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elseif type(sortKey1[i]) == type(0)
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return -1
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elseif type(sortKey2[i]) ==# v:t_number
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elseif type(sortKey2[i]) == type(0)
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return 1
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endif
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let i = i + 1
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let i += 1
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endwhile
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" Keys are identical upto common length.
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